-
-
-
[
Matlab]
LMS.zip
... R0=[1,a1,a2 a1,1+a2,0 a2,a1,1]
p=[1,0,0]
r=inv(R0)*p 计算理论自相关函数
R=[r(1),r(2) r(2),r(1)] 生成理论自相关矩阵
p1=[r(2),r(3)] 生成互相关
h=inv(R)*p1 计算维纳解
Jmin=r(1)-h*p1 计算维纳解时最小均方误差
u=1/sum(eigs(R))
Category:
matlab Upload User：
ljh395020 Size：
1K
-
-
-
[
C/C++]
matrixmultiplication.Rar
beginners achieve matrix multiplication, a simple matrix multiplication think it is practical and writing is not very efficient and can be downloaded from studies oh.
-
-
-
-
-
切换至中文 Over 1 million code package, 10 million code file free download 
